Question #13273

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Answer 1 · 2018-02-11T09:55:02

0 grams of chlorine are produced

However I assume you meant fluorine, so:

$PV=nRT$

$n=(PV)/(RT)$

$n=((1.00atm)(2.01L))/((0.08206L*atmK^-1mol^-1)(273.15K))=0.0897 mol F_2$

$F_2 -> 37.996 g/(mol)$

$(0.0897 mol )(37.996 g/(mol)) = 3.41 g$