Question

Question #c0954

Answer 1

`x=e^2`

Explanation:

In general, an equation with an x in a log and an x outside (or an exponential and outside the exponential such as `xe^x = 1`) are called transcendental equations and do not have exact / analytical solutions.

This one is a bit different. Looking at it, we may have the intuition that `x = e^y`. If we plug this in, the above equation becomes
`e^y y^2 = 4e^2` which clearly is solved by `y = 2` or `x = e^2`.