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Question #8e9bb

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Feb 12, 2018

$15 k N$ $15kN$ opposite to the direction of travel.

Explanation:

$F = m a$ $F=ma$ , we know that much.

We also know that in order to stop the car it has to decelerate from $30 m s^{- 1}$ $30ms^-1$ to $0 m s^{- 1}$ $0ms^-1$ in 3 seconds.

We can figure out that deceleration by

$a = (Deltav)/(Deltat) = (30ms^-1-0ms^-1)/(3s) = 10ms^-2$

Therefore, the force applied to the car must be

$F = 1500kg xx 10ms^-2 = 15,000N = 15kN$

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