What is the Cartesian form of #( 3, (-5pi)/2 ) #?

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Answer 1 · 2018-02-14T08:36:02

Using the formulas:
#x=r*cos(theta)#
#y=r*sin(theta)#

our answer is #(0,-3)# in Cartesian

To convert from Polar coordinates to Cartesian, we must apply the following formulas:

#x=r*cos(theta)#
#y=r*sin(theta)#

where polar form is #(r,theta)#
and Cartesian form is #(x,y)#

for x:
#x=3*cos(-5pi/2) = 3*0 = 0#

#y=3*sin(-5pi/2) = 3*-1 = -3#

thus converting from polar to Cartesian:

Cartesian = #(0,-3)#