Find ∂w/∂u?

Question

Let
w = x^2 + y^2 + z^2,
x = uv, y = u cos(v), z = u sin(v).
Use the chain rule to find ∂w/∂u when (u, v) = (9, 0).

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Answer 1 · 2018-02-19T05:02:56

$w = x^{2} + y^{2} + z^{2}$ $w = x^2 + y^2 + z^2$

$w = {(u v)}^{2} + {(u cos v)}^{2} + {(u sin v)}^{2}$ $w=(uv)^2 + (ucosv)^2 + (usinv)^2$

$d$ $color(white)(d)$

$=>(dw)/(du) = 2uv * (u'v+uv') + 2(ucosv)* (u'cosv+ucosv') +2(usinv)* (u'sinv+usinv')$

$color(white)(d)$

$=>(dw)/(du) = 2uv * (v+u(dv)/(du)) + 2(ucosv)* (cosv-usinv(dv)/(du)) +2(usinv)* (sinv+ucosv(dv)/(du))$

$color(white)(d)$

$=>(dw)/(du) = 2uv^2+ 2u^2(dv)/(du)+ 2ucos^2v-2u^2cosvsinv(dv)/(du) +2usin^2v+2u^2sinvcosv(dv)/(du)$

$color(white)(d)$

$=>(dw)/(du) = 2uv^2+ 2u^2(dv)/(du)+ 2u(cos^2v+sin^2v)$

$color(white)(d)$

$=>(dw)/(du) = 2uv^2+ 2u^2(dv)/(du)+ 2u$