A line passes through (1 ,5 )(1,5) and (8 ,7 )(8,7). A second line passes through (3 ,6 )(3,6). What is one other point that the second line may pass through if it is parallel to the first line?

1 Answer

(10,8)(10,8)

Explanation:

I didn't use math to figure this out, but I'll explain both ways. First the easy way.

To get from (1,5)(1,5) to (3,6)(3,6), you increase xx by 22 and yy by 11, so if you do the same thing to (8,7)(8,7), you get (10,8)(10,8). If you move both points by the same amount, the slope stays the same.

Mathematically, you would have to find the slope of the line made by (1,5)(1,5) and (8,7)(8,7). So you do the slope formula, and you get

"slope" = m = (7-5)/(8-1slope=m=7581

which equals 2/929. Then you use the point-slope formula and input (3,6)(3,6) for the xx and yy variables and 2/929 for the mm variable.

You end up with

y-6=(2/7)(x-3)y6=(27)(x3)

which, when you solve for yy, becomes

y=2/7x+36/7y=27x+367

(I kept the fractions so it would be easier to solve).

Then just pick an xx value and plug it in yo get your yy and you're done. Yay! (You'll notice that plugging in 1010 gets you 56/7567, which is 88)