Question #ce2b1

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Answer 1 · 2018-02-20T06:38:34

See the explanation

A term in a GP is represented by #ar^(n-1)#.

Here , a is the first term.

#-># r is the common ratio.

#-># n is the number of term.

For finding the first four terms calculate #a_2 , a_3 , a_4#

#-> a_1 = 2#

#-> a_2 = 2 times 4^(2-1)#

# " " = 2 times 4#

# " " = 8#

Similarly , #a_3 = 32 and a_4 = 128#

So , the first four terms of the GP are

# 2 , 8 , 32 , 128 #