How do you differentiate $(x + \frac{1}{x}) tan x$ $(x+1/x)tanx$ ?

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Answer 1 · 2018-02-20T15:15:43

$(1 - \frac{1}{x^{2}}) tan x + {sec}^{2} x (x + \frac{1}{x})$ $(1-1/x^2)tanx+sec^2x(x+1/x)$

Using product rule
$d/dx(f(x)g(x))=f'(x)g(x)+f(x)g'(x)$
where $f(x)=x+1/x$ and $g(x)= tanx$

$(1+(-1)x^(-2))tanx+(x+1/x)sec^2x$
$(1-1/x^2)tanx+(x+1/x)sec^2x$

How do you differentiate (x+1/x)tanx(x+1x)tanx(x+1/x)tanx?