Question

Question #e6f7e

Answer 1

1: Is that `f(x)=sqrt(x)+6`?

Domain=[0 , ∞ )
Range=[6, ∞ )

2: Or is that `f(x)=xsqrt(+6)`?

Domain=(- ∞ , ∞ )
Range=(- ∞, ∞ )

Explanation:

1: Domain is the possible values x can take on, since x is inside the square root, then x is restricted to non-negative numbers only. Therefore, the range of f(x) is [6, ∞ ) since if x is 0 (lower limit of the domain of x), then f(x) is 6.

2: Since it is only multiplication, then the domain and the range is the set of all real numbers.