Question #b6919

1 Answer
Feb 20, 2018

The boat is moving at #20/sqrt(3) kph# or #11.54 kph#

Explanation:

We want the passenger to think that the boat is moving north, so we don't want the boat moving away or towards the passenger. So the **velocity of the boat in the east direction has to be the same as the velocity of the ship in the east direction ** so the passenger doesn't see the boat get closer or farther away.

We have a triangle that looks like this
mine

And we are solving for X .

We know that #cos(30) = 10/x#

Rearranging gives #x = 10/cos(30)#

So #x = 10/(sqrt(3)/2) = 20/sqrt(3)#

So the velocity of the boat is #11.54 kph# going 30 degrees to the east.