Question

How do I calculate mole fraction of glucose in a solution?

Doc weighs 15.42 g of glucose (C6H12O6) and 75.36 g of ethanol (C2H5OH). he dissolves the glucose in the ethanol to make his solution. Calculate the mole fraction of the solution.

Answer 1

The formula :

Mole fraction of solute = `"Amount of solute (in mols)"/"Sum of amount of solute and solvent (in mols)"`

Explanation:

That means, say you have 90 grams of Glucose in 180 grams of water. So the number of moles of glucose present is `90/180 = 0.5` (180 is the relative molecular mass of glucose) and the number of moles of water is `180 / 18 = 10` (18 is the relative molecular mass of water).
So, here the mole fraction of glucose would be (`0.5/(0.5+10)`)

P.S. Solve your problem with the formula. There is a mistake in your question. There's nothing called the 'mole fraction of the solution'.