Write the equation in standard form for the quadratic equation whose vertex is at (-3,-32) and passes through the point (0,-14) ?

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Answer 1 · 2018-02-21T17:19:48

#y=2x^2+12x-14#

Vertex form is given by:

#y=a(x-h)^2+k# with #(h,k)# as the vertex.

Plug in the vertex.

#y=a(x+3)^2-32#

Plug in the point:

#-14=a(0+3)^2-32#

#-14=9a-32#

#9a=18#

#a=2#

The vertex form is:

#y=2(x+3)^2-32#

Expand:

#y=2(x^2+6x+9)-32#

#y=2x^2+12x+18-32#

#y=2x^2+12x-14#