Mass of 1.50 mol of carbon tetrafluoride?

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Answer 1 · 2018-02-21T19:47:46

Mass of 1.5 moles of $CF_4$ = $132 grams$

Molecular Mass of Carbon Tetrafluoride ( $CF_4$ )

= $(1 * MW of C) + (4* MW of F)$
= $(1*12 g/(mol)) + (4*19g/(mol))$
= $88 g/(mol)$

Number of Moles = Mass/Molecular Mass

Mass = Number of Moles * Molecular Mass

Therefore, Mass of 1.5 moles of $CF_4$ is

= $88 g/(mol) * 1.5 mol$

= $132 grams$