14z + 96 = 28z - 100
z = ?
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"Question #a738e"
Move all terms containing #z# to one side and keep all other terms on another side:
#14z-14z+96=28z-14z-100z#
#96=28z-14z-100z#
(If we want to move #14z# from the left side to the right side, we'll need to subtract #14z# from each side.)
Now, simplify the side containing #z#'s by subtracting:
#96=-86z#
Solve for #z# . This means dividing each side by #-86#, which would mean #-86# cancels out on the left side.
#(-96/86)=((cancel-86)/(cancel-86))z#
#z=(-96/86)#
Simplify:
#z=-48/43#
Combine like terms on both sides.
#14z+96=28z-100#
#14z-14z+96=28z-14z-100#
#96=14z-100#
#96+100=14z-100+100#
#196=14z#
Divide
#196/14=(14z)/14#
#z=14#
We can start by adding 100 to both sides, and we get:
#14z+196=28z#
We want to get the constant on one side and the variables on the other. So we can subtract #14z# from both sides, and we get:
#196=14z#
Swapping the sides:
#14z=196#
We can divide both sides by #14# to get:
#z=14#