Question

Question #9fee3

Answer 1

`((7n^2)(x+4))/(cancel((x-3))(x-4))xxcancel(x-3)/((x+8)(x+6))`
You get
`((7n^2)(x+4))/((x-4)(x+8)(x+6))`

Now you can expand it or leave it like this
`(7xn^2)/((x^2+4x-32)(x+6))`

Expand it further
`(7n^2x)/(x^3+6x^2+4x^2+24x-32x-192)`
Solve
`(7n^2x)/(x^3+10x^2-8x-192)`
If you want to factorize it.... factorize it...
`(7n^2x)/(x^2(x+10)-8(x+24))`