Question #9fee3

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1 Answer
Kushagra
Feb 22, 2018

#((7n^2)(x+4))/(cancel((x-3))(x-4))xxcancel(x-3)/((x+8)(x+6))#
You get
#((7n^2)(x+4))/((x-4)(x+8)(x+6))#

Now you can expand it or leave it like this
#(7xn^2)/((x^2+4x-32)(x+6))#

Expand it further
#(7n^2x)/(x^3+6x^2+4x^2+24x-32x-192)#
Solve
#(7n^2x)/(x^3+10x^2-8x-192)#
If you want to factorize it.... factorize it...
#(7n^2x)/(x^2(x+10)-8(x+24))#

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