How do you solve #(2b + 5) ( b - 3) = b ^ { 2} - 3#?

1 Answer
Shreya
Feb 22, 2018

b=4 or -3

Explanation:

#(2b-5)(b-3)=b^2-3#
Simplifying,
#2b^2-b^2-6b+5b-15+3=0#
or,#b^2-b-12=0#
Carrying out middle term factorisation,we have,
#b^2-4b+3b-12=0#
#(b-4)(b+3)=0#
Thus,#b-4=0# or #b+3=0#
We have, #b=4 or -3#

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