How do solve for x in a log question?

Question

Solve for x: $2log_"10"x+3 = 5log_"10"x$

1131 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-23T09:07:16

$x=10$

Let's start by simplifying the equation.

$2log_10 x+3 = 5log_10 x$
$3 = 3log_10 x$
$1 = log_10 x$

Now, since $log_a b = c$ is equivalent to $a^c = b$ , we can change our equation to,

$10^1 = x$
$x = 10$
$square$