How do you solve "-8-x=x-4x"?

Question

3037 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-23T21:35:18

Read explanation.

$- 8 - x = x - 4 x$ $-8 - x = x - 4x$

You can subtract $4 x$ $4x$ from $x$ $x$ and get:

$- 8 - x = - 3 x$ $-8 - x = -3x$

Then you add the $x$ $x$ to both sides, which cancels out the $x$ $x$ on the left side and get:

$- 8 = - 2 x$ $-8 = -2x$

Then divide both sides by $- 2$ $-2$ and get:

$4 = x$ $4 = x$

Hope that helps.

Answer 2 · 2018-02-24T01:29:50

$x = 4$ $x=4$

$- 8 - x = x - 4 x$ $-8-x=x-4x$

$- 8 - x = - 3 x$ $-8-x=-3x$

Add $3 x$ $3x$ to both sides#

$- 8 - x + 3 x = - 3 x + 3 x$ $-8-x+3x=-3x+3x$

$- 8 - x + 3 x = 0$ $-8-x+3x=0$

$- 8 + 2 x = 0$ $-8+2x=0$

Then add $- 8$ $-8$ to both sides

$- 8 + 2 x + 8 = 0 + 8$ $-8+2x+8=0+8$

$2 x = 8$ $2x=8$

Finally, divide both sides by $2$ $2$

$\frac{2 x}{2} = \frac{8}{2}$ $(2x)/2=8/2$

$x = 4$ $x=4$