A mixture of $"N"_2$ , $"O"_2$ . and $"CO"_2$ has a total pressure of $"740 torr"$ In this mixture, the partial pressure of $"N"_2$ is $"120 torr"$ and the partial pressure of $"O"_2$ is $"400 torr"$ . What is the partial pressure of $"CO"_2$ ?

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Answer 1 · 2018-02-24T09:40:48

$"220 torr"$

From Dalton's Law of Partial Pressures, the total pressure of a mixture of gases is the sum of the partial pressures of each gas.

Therefore, the partial pressure of $"CO"_2$ is

$"740 torr " - " 120 torr " - " 400 torr = 220 torr"$

Answer 2 · 2018-02-24T09:42:47

$220"torr"$

According to Dalton's Law of Partial Pressures,

$P_"total"=SigmaP_i$ , or $P_"total"=P_1+P_2+....P_n$

Here, we can write the above as:

$P_"total"=P_(N_2)+P_(CO_2)+P_(O_2)$

Here,

$P_"total"=740"torr"$

$P_(N_2)=120"torr"$

$P_(O_2)=400"torr"$

Inputting, we get:

$740=120+400+P_(CO_2)$

$740=520+P_(CO_2)$

$P_(CO_2)=220"torr"$

A mixture of "N"_2"N"_2, "O"_2"O"_2. and "CO"_2"CO"_2 has a total pressure of "740 torr""740 torr" In this mixture, the partial pressure of "N"_2"N"_2 is "120 torr""120 torr" and the partial pressure of "O"_2"O"_2 is "400 torr""400 torr". What is the partial pressure of "CO"_2"CO"_2 ?