How do you determine the equation of the line that passes through the points (-5,7) and (6,15)?

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Answer 1 · 2018-02-24T11:10:50

I assume for this question you're asking about a straight line.

$y = 8/11 x + 117/11$

First, work out the gradient by finding $(dely)/(delx)$ ,

$m = (15-7)/(6 + 5) = 8/11$

Then plug in the original values for one point,

$15 = 8/11(6) + c$

$c = 117/11$

Therefore,

$y = 8/11 x + 117/11$