Question

What is the standard form of `y=-(x - 1) (x^2 +6)(x/3 + 2)`?

Answer 1

`y=-1/3x^4-5/3x^3-10x+12`

Explanation:

`y=-(x-1)(x^2+6)(x/3+2)`

`y=-(x^3+6x-x^2-6)(1/3)(x+6)`

`y=-1/3(x^3-x^2+6x-6)(x+6)`

`y=-1/3(x^4-x^3+6x^2-6x+6x^3-6x^2+36x-36)`

`y=-1/3(x^4+5x^3+30x-36)`

`y=-1/3x^4-5/3x^3-10x+12`
Which fits the standard form of `y=Ax^4+Bx^3+Cx^2+Dx+E`