What is the dissociation reaction of sodium acetate in water?

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What is the dissociation reaction of sodium acetate in water?

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Answer 1 · 2018-02-26T05:48:02

Well of course there is the ionization reaction....

Explanation:

$H_{3} C - C O_{2}^{-} N a^{+} (s) H_{2} O - - \to H_{3} C - C O_{2}^{-} + N a^{+}$ $H_3C-CO_2^(-)Na^(+)(s)stackrel(H_2O)rarrH_3C-CO_2^(-) + Na^(+)$

But possibly you mean the acid-base reaction that acetate ion, as the conjugate base of a weak acid, undergoes...

$H_{3} C - C O_{2}^{-} + H_{2} O (l) ⇌ H_{3} C - C O_{2} H + H O^{-}$ $H_3C-CO_2^(-) + H_2O(l) rightleftharpoons H_3C-CO_2H + HO^-$

...and the extent of this equilibrium could be very easily quantified...of course this is an association reaction....

Answer 2 · 2018-02-26T05:55:08

Sodium acetate would dissociate in water to give $N a^{+}$ $Na^+$ and $C H_{3} C O O^{-}$ $CH_3COO^-$ ions which would slightly associate in water to give a little $O H^{-}$ $OH^-$ .

$C H_{3} C O O^{-} (a q) + H_{2} O (l) \to C H_{3} C O O H (a q) + O H^{-} (a q)$ $CH_3COO^(-)(aq) + H_2O(l) rarr CH_3COOH(aq) + OH^(-)(aq)$

Explanation:

Water is a polar molecule because Oxygen has a higher electronegativity than Hydrogen. As a result, Oxygen has a $δ^{-}$ $delta^-$ charge and Hydrogen has a $δ^{+}$ $delta^+$ charge.

Water consists of $H^{+}$ $H^+$ and $O H^{-}$ $OH^-$ ions.

Sodium acetate is an ionic compound formed from $N a^{+}$ $Na^+$ and $C H_{3} C O O^{-}$ $CH_3COO^-$ ions, which dissociates in water due to its polarity.

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What is the dissociation reaction of sodium acetate in water?

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