Why is CuI2 unstable?

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Why is CuI2 unstable?

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Answer 1 · 2018-02-26T08:49:32

$C u I_{2}$ $CuI_2$ will have a redox reaction

Explanation:

If we bring together $C u^{2 +}$ $Cu^(2+)$ and $I^{-}$ $I^-$ ions the copper(II) will be reduced to copper(I), while part of the iodide will be oxidized to iodine.
Copper(I)iodide is badly soluable:

$2 C u^{2 +} (a q) + 4 I^{- (a q)} \to 2 C u I (s) + I_{2} (a q)$ $2Cu^(2+)(aq)+4I^-(aq) -> 2CuI(s)+I_2(aq)$

The partial reactions being:
$2 C u^{2 +} (a q) + 2 e^{-} \to 2 C u^{+} (a q)$ $2Cu^(2+)(aq)+2e^(-) ->2Cu^+(aq)$ = reduction
$2 I^{-} (a q) \to I_{2} (a q) + 2 e^{-}$ $2I^(-)(aq) ->I_2(aq)+2e^-$ = oxidation
$2 C u^{+} (a q) + 2 I^{-} (a q) \to 2 C u I (s)$ $2Cu^+(aq) +2I^(-)(aq)->2CuI(s)$ = precipitation

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Why is CuI2 unstable?

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