Simply this 5√81q^3 ?

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Answer 1 · 2018-02-26T18:21:08

See explanation...

Alright, lets begin with a simple square root rule.

$\sqrt{A B} = \sqrt{A} \cdot \sqrt{B}$ $sqrt(AB)=sqrtA*sqrtB$

Understanding this, lets break your problem into two different squares.

$= 5 \sqrt{81} \cdot \sqrt{q^{3}}$ $=5sqrt81*sqrt(q^3$

We know that the $\sqrt{81}$ $sqrt81$ is the same as $9$ $9$ because $9^{2} = 81$ $9^2=81$

$= 5 \cdot 9 \sqrt{q^{3}}$ $=5*9sqrt(q^3$ $\to$ $->$ $= 45 \sqrt{q^{3}}$ $=45sqrt(q^3$

At this point, we should split the square root into two using the same rule as above.

$= 45 \sqrt{q^{2}} \cdot \sqrt{q}$ $=45sqrt(q^2)*sqrtq$

$=45cancelsqrt(q^cancel2)*sqrtq$ $->$ $45qsqrtq$

So the simplified version of $5sqrt(81q^3)$ is $45qsqrtq$

Hope this helped!
~Chandler Dowd