How do you graph the system of linear inequalities $3 y - x < 15$ $3y - x < 15$ and $y + 2 x \geq - 1$ $y + 2x \geq - 1$ ?

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Answer 1 · 2018-02-28T09:20:15

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You have to graph each inequalities following the same principles that are used representing functions graphs.

The intersection between both areas is the requested solution. See graph (dark blue zone=solution)

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How do you graph the system of linear inequalities 3y−x<153y - x < 15 and y+2x≥−1y + 2x \geq - 1?