How do you solve $\frac{x - 4}{2} = - \frac{6}{4}$ $(x-4)/2 = -6/4$ ?

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Answer 1 · 2018-03-02T06:07:24

$x = 1$ $x=1$

simplify the fraction by dividing the top and bottom by 2
$\frac{x - 4}{2} = - \frac{3}{2}$ $(x-4)/2=-3/2$

multiply both sides by 2
$\frac{2 (x - 4)}{2} = \frac{- 3 \cdot 2}{2}$ $(2(x-4))/2=(-3*2)/2$

the 2s on the top and bottom cancel out
$x - 4 = - 3$ $x-4=-3$

add 4 to both sides
$x - 4 + 4 = - 3 + 4$ $x-4+4=-3+4$

$x = 1$ $x=1$

How do you solve (x-4)/2 = -6/4x−42=−64(x-4)/2 = -6/4?