How do you simplify $(\sqrt{5} + \sqrt{2}) (\sqrt{5} - \sqrt{2})$ $(sqrt5 + sqrt2) (sqrt5 - sqrt2)$ ?

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Answer 1 · 2018-03-02T15:44:00

$3$ $3$

A math rule states that:

$(a + b) (a - b) = a^{2} - b^{2}$ $(a+b)(a-b)=a^2-b^2$

Here, $a = \sqrt{5}$ $a=sqrt5$
Here, $b = \sqrt{2}$ $b=sqrt2$

Substituting the values:

$(\sqrt{5} + \sqrt{2}) (\sqrt{5} - \sqrt{2}) = {(\sqrt{5})}^{2} - {(\sqrt{2})}^{2}$ $(sqrt5+sqrt2)(sqrt5-sqrt2) = (sqrt5)^2-(sqrt2)^2$

Cancelling out:

$\to (5) - (2)$ $->(5)-(2)$

$= 5 - 2$ $=5-2$

$= 3$ $=3$

Thus, solved

How do you simplify (√5+√2)(√5−√2)(sqrt5 + sqrt2) (sqrt5 - sqrt2)?