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Answer 1 · 2018-03-02T16:16:33

See below

$F=QvB$
(F is force , Q is charge , v is velocity , B is magnetic field)

$color (red)(F=ma)$

$=>ma=QvB$

$=>(ma)/(Qv)=B$

$=>(m(v/t))/(Qv)=B$

$=>(mv)(Qvt)=B$

$=>sqrt (m^2v^2)/(Qd)=B$

$=>sqrt (2mk)/(Qd)=B$
Hope it helps