A volume of a gas is 20.4 L when the pressure is 925 kPa. At constant temperature, a change in pressure causes the volume of the sample to change. If the new volume is 30.6 L, what is the new pressure?

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Answer 1 · 2018-03-02T21:22:48

$"617 kPa"$ .

This is what we're given:

We have to find $P_2$ , or the final pressure—to do this, we can use Boyle's law!:

$P_1V_1 = P_2V_2$

We can rearrange this to have only $P_2$ on one side:

$P_2 = (P_1V_1)/V_2$

Plugging in all of the values, we get:

$(P_1V_1)/V_2 = ("925 kPa" xx "20.4" cancel("L"))/("30.6" cancel("L"))$

$P_2 = "616.667 kPa"$

Rounding this off to $3$ significant figures (which has what has been given to us in the question), we get $"617 kPa"$ . :)