How do you solve $- \frac{x}{3} - 5 = 2 x$ $-x/3-5=2x$ ?

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Answer 1 · 2018-03-03T04:26:16

$x = - \frac{5}{7}$ $x=-5/7$

Times both sides by three:

$(- \frac{x}{3} - 5) \cdot 3 = 2 x \cdot 3$ $(-x/3 -5)*3=2x*3$

$- x - 15 = 6 x$ $-x-15=6x$

Then add $x$ $x$ to both sides:

$- x - 5 + x = 6 x + x$ $-x-5+x=6x+x$

$- 5 = 7 x$ $-5=7x$

Finally, divide both sides by 7 to get $x$ $x$ on its own:

$- \frac{5}{7} = \frac{7 x}{7}$ $-5/7=(7x)/7$

$- \frac{5}{7} = x$ $-5/7=x$

Therefore:

$x = - \frac{5}{7} or \approx 0.71$ $x=-5/7 or ≈ 0.71$

How do you solve -x/3-5=2x−x3−5=2x-x/3-5=2x?