What is the derivative of $sin^3x$ ?

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Answer 1 · 2018-03-03T05:41:22

Basic formula:

$d/(dx)x^n=nx^(n-1)$

$d/dx(sinx)=cosx$

Now, let's move to the question:
$color(white)=d/dx(sin^3x)$
$=(3sin^2x)×(d/dx(sinx))$
$=3sin^2xcosx$

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