How do you factor $1 - 4y^2$ ?

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Answer 1 · 2018-03-03T09:25:45

$(1-2y)(1+2y)$

$"this is a "color(blue)"difference of squares"$

$•color(white)(x)a^2-b^2=(a-b)(a+b)$

$"here "a=1" and "b=2y$

$rArr1-4y^2=(1-2y)(1+2y)$

Answer 2 · 2018-03-03T09:27:32

$(1+2y)(1-2y)$

$color(blue)(1-4y^2)$

$=>color(blue)((1)^2 - (2y)^2)$

We have an identity for $color(green)(a^2 - b^2)$ which is equal to $color(green)((a+b)(a-b))$ .

So , $color(red)((1)^2 - (2y)^2)$

$=> color(red)((1+2y)(1-2y))$

How do you factor 1 - 4y^21 - 4y^2?