How do you solve #|2x - 4| + 2> 8#?
1 Answer
Explanation:
In order to solve:
Find a way to get
First, subtract
Giving you:
Now, set up an OR statement.
This looks like this:
(absolute value quantity) > (number on other side)
OR
(absolute value quantity) < -(number on other side)
Which would look like this when substituted:
OR
---
Now, we solve for each by taking away the absolute value signs.
-
#2x−4 > 6#
[add 4 to both sides]
#2xcancel(-4)cancel(+4) >6 +4#
[divide by 2 on both sides]
#(cancel(2)x)/cancel(2) > 10/2#
[simplify]
Solution :#x>5#
.
. -
#2x−4< - 6#
[add 4 to both sides]
#2xcancel(-4)cancel(+4) < -6 +4#
[divide by 2 on both sides]
#(cancel(2)x)/cancel(2) < (-2)/2#
[simplify]
Solution :#x<-1#
Now, we combine both solutions to get the final answer.