Question

You have 10 grams of C10H10O2. How many moles are present? How many molecules are present?

Answer 1

Well the formula mass is `162.18* g*mol^-1`

Explanation:

And so we take the quotient....

`"Molar quantity"="Mass"/"Molar mass"=(10.0*cancelg)/(162.18*cancelg*mol^-1)`

`=0.06171*1/(1/(mol))=0.0617*mol`

And we know that there are `6.022xx10^23*"particles"*mol^-1`..

And so we take the product....

`6.022xx10^23*"particles"*mol^-1xx0.0617*mol=3.71xx10^22*"mollykewells"`

How many carbon atoms present in this quantity?

Answer 2

0.062 moles and 3.7*10^22 molecules

Explanation:

Molecular mass of `C_10H_10O_2` is `162`, therefore `10` grams are `10/162 = 0.062` moles. Each mole contains the Avogadro's number of molecules `0.062*6.02*10^23=3.7*10^22`