How do you solve #x= \log _ { 10} \root(6) { 10}#?

1 Answer
Mar 4, 2018

#x=1/6#

Explanation:

We know that

#log_(10)(10^a) = a#

So it would be nice to get our equation in a form like that. We need to recall that a root is the same as the reciprocal of the power, i.e.:

#\root(b)(y) = y^(1/b)#

Therefore:

#x = log_(10)(\root(6)(10))=log_10(10^(1/6)) = 1/6#