How do you solve the system of equations x+y=−4 and −8x+3y=21?

1 Answer
Shreya
Mar 4, 2018

x=-3 and y=-1

Explanation:

We have, x+y=−4
or,y=−4−x
Multiplying both sides with 3,we have,
3y=−12−3x
Substituting the value of 3y in the equation 3y−8x=21,we get,
−12−3x=21+8x
Or,−33=11x
Thus,x=−3
Putting the value of x in first equation,we get y as −4−(−3) or y=−1

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