What's the equation of the line through (-10,3) and (-8,-8)?

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What's the equation of the line through (-10,3) and (-8,-8)?

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Answer 1 · 2018-03-05T06:12:38

$y = (- \frac{11}{2}) x - 52$ $y=(-11/2)x-52$

Explanation:

$(- 10, 3)$ $(-10,3)$ and $(- 8, - 8)$ $(-8,-8)$
The slope of the line between $A (x_{1}, y_{1})$ $A(x_1,y_1)$ and $B (x_{2}, y_{2})$ $B(x_2,y_2)$ is:
$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$
The equation of the line AB in point slope form is:
$y - y_{1} = m (x - x_{1})$ $y-y_1=m(x-x_1)$
So in this case:
$m = \frac{- 8 - 3}{- 8 - (- 10)} = - \frac{11}{- 8 + 10} = - \frac{11}{2}$ $m=(-8-3)/(-8-(-10)) = -11/(-8+10)=-11/2$
$y - 3 = - \frac{11}{2} (x + 10)$ $y-3=-11/2(x+10)$ => point slope form
$y - 3 = (- \frac{11}{2}) x - 55$ $y-3=(-11/2)x-55$
$y = (- \frac{11}{2}) x - 52$ $y=(-11/2)x-52$ => slope intercept form

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What's the equation of the line through (-10,3) and (-8,-8)?

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