How do you solve #22= - 2s + 4#?

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Answer 1 · 2018-03-05T06:58:12

#s = 9#

#22=-2s+4#

#22color(red)(-4)=-2s color(red)(cancel(color(black)(+4)-4))#

#18/color(red)(2)=-color(red)((cancel(2)color(black)(s))/cancel(2)#

#color(red)(-)9 = color(red)(cancel( -color(black)(-))color(black)(s)#

#s = - 9#

We can prove this by substituting the pronumeral for it's given value in the equation.

#22=-2 xx - 9+4#

#22= 18 +4#