Question

The average molecular speed in a sample of CO2 gas at a certain temperature is 384 m/s. The average molecular speed in a sample of H2 gas is m/s at the same temperature.?

Answer 1

1801 m/s

Explanation:

Average Molecular Speed
`v = sqrt((8RT)/(piM))`

i.e `v` is inversely proportional to `M^(1/2)`

so `((V1)/(V2)) = ((M2)/(M1))^(1/2)`

`((384)/(V2)) = ((2)/(44))^(1/2)`

`V2 = 1801 m/s`