2atm 20°c temperature 10g O2 volume 3.76 R value?

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Answer 1 · 2018-03-05T14:43:55

#R=0.082 \ "L atm K"^-1 \ "mol"^-1#

According to the Ideal Gas Law:

#PV=nRT#

This asks us to solve for #R#:

#R=(PV)/(nT)#

Here,

#P=2 \ "atm"#

#V=3.76 \ "L"#

#n=10/15.999=0.312 \ "mol"#

#T=293.15 \ "K"#

Inputting:

#R=(2*3.76)/(0.312*293.15)#

#R=0.082 \ "L atm K"^-1 \ "mol"^-1#