How do you evaluate #[( 9\times 2) - ( 3\times 4) ] \times 2#?

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Answer 1 · 2018-03-05T23:18:45

12

#[(9*2) -(3*4)] *2#

#(18 - 12)*2#

#6*2#

12

Answer 2 · 2018-03-05T23:25:06

The result is #12#.

First, do the steps on the innermost parentheses, then the outer ones:

#color(white)=[(9xx2)-(3xx4)]xx2#

#=[stackrel(18) overbrace((9xx2)) - stackrel(12) overbrace((3xx4))] xx2#

#=[18-12]xx2#

#=[stackrel6 overbrace(18-12)]xx2#

#=6xx2#

#=stackrel12 overbrace(6xx2)#

#=12#