How do you solve #-3(x+3)=-9#?

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Answer 1 · 2018-03-06T13:25:43

#x=0#

We are given: #-3(x+3)=-9#

#x+3=(-9)/-3=3#

#x=3-3#

#x=0#

Answer 2 · 2018-03-06T13:27:22

#color(magenta)(x=0#

#-3(x+3)=-9# [Opening the brackets]

#-3x-9=-9# [By transposing method]

#-3x=-9+9#

#-3x=0#

#x=0/-3#

#color(magenta)(x=0#

~Hope this helps! :)