Question

What is the vertex of `y=3x^2 +12x - 16`?

Answer 1

`(-2, -28)`

Explanation:

To find the x-coordinate of the vertex, you do `-b/(2a)`

Where `a = 3 , b=12 , c=-16`

You then take that answer. Here that is `-12/6=-2`, and then input that value as the `x` value.

`3(-2)^2+12(-2)-6=12-24-16=-28`

So the coordinates are `(-2,-28)`