How do you factor the expression #2x^2-5x-3 #? Algebra Polynomials and Factoring Factoring Completely 1 Answer Chanelle K. Mar 6, 2018 the answer is #(2x+1)(x-3)# Explanation: #-6*1=-6# & #6+1=-5# #2x^2-6x+x-3# take out #^# #2x(x-3)+1(x-3)# answer#= (2x+1)(x-3)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1112 views around the world You can reuse this answer Creative Commons License