How do you solve $6 x^{2} + 24 x = 0$ $6x^2 + 24x = 0$ ?

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Answer 1 · 2018-03-07T12:58:01

$the answer is {-4,0}$ $"the answer is {-4,0}"$

$6 x^{2} + 24 x = 0$ $6x^2+24x=0$

$Rearrange the equation like the fallowing.$ $"Rearrange the equation like the fallowing."$

$6 x^{2} = - 24 x$ $6x^2=-24x$

$Divide the both sides of equation by 6.$ $"Divide the both sides of equation by 6."$

$cancel(6)x^2=-cancel(24)x$

$x^2=-4x$

$"Divide the both sides of equation by 'x'."$

$cancel(x)^2=-4cancel(x)$

$x=-4$

How do you solve 6x^2 + 24x = 0 6x2+24x=06x^2 + 24x = 0 ?