How do you simplify $\frac{24 x^{3} y + 12 x^{2} y^{2} - 16 x y^{3}}{4 x y}$ $(24x^3y + 12x^2y^2 - 16xy^3)/(4xy)$ ?

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How do you simplify $\frac{24 x^{3} y + 12 x^{2} y^{2} - 16 x y^{3}}{4 x y}$ $(24x^3y + 12x^2y^2 - 16xy^3)/(4xy)$ ?

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Answer 1 · 2018-03-07T13:23:30

$6 x^{2} + 3 x y - 4 y^{2}$ $6x^2 + 3xy - 4y^2$

Explanation:

$\frac{24 x^{3} y + 12 x^{2} y^{2} - 16 x y^{3}}{4 x y}$ $(24x^3y + 12x^2y^2 - 16xy^3)/(4xy)$

$\Rightarrow \frac{24 x^{3} y}{4 x y} + \frac{12 x^{2} y^{2}}{4 x y} - \frac{16 x y^{3}}{4 x y}$ $=> (24x^3y)/(4xy) + (12x^2y^2)/(4xy) - (16xy^3)/(4xy)$

$\Rightarrow 6 x^{2} + 3 x y - 4 y^{2}$ $=> 6x^2 + 3xy - 4y^2$

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How do you simplify $\frac{24 x^{3} y + 12 x^{2} y^{2} - 16 x y^{3}}{4 x y}$ $(24x^3y + 12x^2y^2 - 16xy^3)/(4xy)$ ?

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Explanation:

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How do you simplify $\frac{24 x^{3} y + 12 x^{2} y^{2} - 16 x y^{3}}{4 x y}$ $(24x^3y + 12x^2y^2 - 16xy^3)/(4xy)$ ?