Sec^2 (π/4) ?

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Answer 1 · 2018-03-07T13:34:19

#sec(pi/4)=2#

#sec(x)=1/cos(x)#

#sec^2(x)=(1/cos(x))^2 = 1/cos^2(x) = 1/(cos(x))^2#

#sec(pi/4)=1/(cos(pi/4))^2# #=># #{cos(pi/4)=sqrt2/2}#

#sec(pi/4)=1/(sqrt2/2)^2#

#sec(pi/4)=1/(2^(2*1/2)/2^(1*2)#

#sec(pi/4)==1/(2^1/2^2)#

#sec(pi/4)=1/(2/4)#

#sec(pi/4)=1/(1/2)#

#sec(pi/4)=1/1 -: 1/2#

#sec(pi/4)=1/1 * 2/1#

#sec(pi/4)=2/1#

#sec(pi/4)=2#

Thus, we have our answer.