How do you solve #9/4=(r-10)/r#?

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Answer 1 · 2018-03-07T21:39:43

#r=-8#

#9/4=(r-10)/r#

Start with cross multiply

#(9)(r)=4(r-10)#

#9r = 4r - 40#

Add #-4r# on both sides

#9r - 4r = 4r - 40 - 4r#

#5r = -40#

Divide both sides by #5#

#(cancel5r)/cancel5=(-40)/5#

#r=-8#