What are the solutions of $x^{2} + 6 x - 6 = 10$ $x^2+6x-6= 10$ ?

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Answer 1 · 2018-03-08T00:44:29

$x = 2 or x = - 8$ $x=2 or x=-8$

$x^{2} + 6 x - 6 = 10$ $x^2 +6x - 6 =10$

Start by subtracting $10$ $10$ from both sides

$x^{2} + 6 x - 6 - 10 = 10 - 10$ $x^2 + 6x - 6 - 10 = 10 - 10$

$x^{2} + 6 x - 16 = 0$ $x^2 + 6x - 16 =0$

Then factorize the left side

$(x - 2) (x + 8) = 0$ $(x-2)(x+8)=0$

Set factors equal to $0$ $0$

$x - 2 = 0 or x + 8 = 0$ $x-2=0 or x+8=0$

$x = 0 + 2 or x = 0 - 8$ $x=0+2 or x=0-8$

$x = 2 or x = - 8$ $x=2 or x=-8$

What are the solutions of x2+6x−6=10x^2+6x-6= 10?