What is the slope of the line passing through the following points: # (5, -6) , (2, 5)#?

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Answer 1 · 2018-03-08T03:11:39

#Slope = -11/3#

#color(blue)("Slope of a line (m)" = (y_1-y_2)/(x_1-x_2))#

Here , #color(red)(x_1=5)#

#color(red)(y_1=-6)#

#color(red)(x_2=2)#

#color(red)(y_2=5)#

Put these values in the slope equation

#=> color(magenta)(Slope = ((-6)-(5))/((5)-(2)))#

#=> color(magenta)(Slope = (-6-5)/(5-2))#

#=> color(green)(Slope = -11/3)#

Answer 2 · 2018-03-08T03:16:48

Hey!
Algebra is gr8. In this case, what you would do is use the slope formula; #m = (y_2 - y_1)/ (x_2 - x_1)#.

#m = (y_2 - y_1)/(x_2 - x_1)#

Where m = slope, and each 'y' or 'x' term is inserted from your coordinate points!

(5, -6)(2, 5)

'5' is #x_1#
'-6' is #y_1#
'2' is #x_2#
'5' is #y_2#
(Respectively, if you haven't noticed :)

Plug them in!

#m=(5 - (-6))/(2 -5)#
(Remember, two negatives cancel out, so the top will be 5 + 6)

#m=(5+6)/(2-5)#
#m = 11/-3#

Your slope is #-11/3#!
Or approximately 3.67 (rounded)